- Egypt international Mohamed Salah has been named as the 2018 African best player
- The Liverpool striker won the award in Dakar, Senegal beating Sadio Mane and Aubameyang
- Salah was superb last season scoring 32 Premier League goals for Liverpool
Liverpool striker Mohamed Salah has been named as the 2018 African best player of the year in a ceremony held in Dakar, Senegal on Tuesday night, January 8.
The announcement was made by CAF who are the African's football governing body as the Egypt international defeated Liverpool teammate Sadio Mane and Arsenal star Pierre-Emerick Aubameyang to win the award.
Salah also beat these two players last year for him to win the player of the year award for the first time in his career.
This is the fifth straight nomination for Arsenal and Gabonese striker Emerick Aubameyang who won the player of the year award in 2015.
Last season in the Premier League, Mohamed Salah scored 32 goals for Liverpool winning the golden boot award for the first time.
And already this season, the former Chelsea and Roma star has scored 13 Premier League goals as his club Liverpool stay top on the English topflight standings.
Earlier, Legit.ng had reported how Liverpool superstar Mohamed Salah explained the significant role his father played for him to become one of the best footballers in the world.
Since the Egypt international came into the Premier League, he has been impressive for Liverpool helping them reach the final of the 2017/18 Champions League losing to Real Madrid in kiev.
And while growing up in Egypt, Mohamed Salah nearly quit football because of the long distance he would travel to for training sessions.
NAIJ.com (naija.ng) -> Legit.ng We have updated to serve you better
Ferdinand reveals admiration for Okocha, why he quit boxing and Man U problems | Legit TV